Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what online casinos was the new weight of the oranges, in kilograms?
(A) 4.9
(B) 4.8
(C) 2.5
(D) 2
(E) 0.2
Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what online casinos was the new weight of the oranges, in kilograms?
4.9
A
5 – (5*0,02)= 4,9
(C) 2.5
Artem, (C) это правильный ответ. Поделитесь, пожалуйста, своим решением
C
Larisa, поделитесь, пожалуйста, как вы пришли к правильному ответу
концентрация уменьшилась на 2% значит:
0.96 x 5= 4.8 kg
5kg*98%-(98%*2%)=4.8
Рассудите нас уже!
Всем спасибо за мысли! Еще немного терпения
1) The concentration of water decreased by 2%, not by 2 percentage points. Thus, we should calculate the decrease of the concentration of water in such a way: 98% * 2% = 1,96%
2) The decrease of water in kilograms: 5 * 1,96% = 0,098
3) The new weight of the oranges in kilograms: 5 – 0,098 = 4,902 ≈ 4,9
The correct answer is (A)
B
Еще один вариант решения:
Total amount × percent decrease = decrease in amount
Total amount – decrease in amount = net result
5 × 0.02 = 0.1
5 – 0.1 = 4.9
(A)
4,9=(5*96%)/98%
4.9
A) 4.9 (around)
Great question, Olga!
and what is your answer, Charles?
Answer C.
5 kg= 98% of water and 2% of peel for instance.
2%= 100 gm.
Then we have 96 % of water, hence 4 % of peel.
If our 100gm of peel is 4% of oranges now, so the weight of oranges should be 2,5 kg.
That’s the correct answer and solution! Thank you, victoria!
If you have another approach or any questions, please, share